3[3(b-5)+17]-[3(3b-2)+5]=

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Solution for 3[3(b-5)+17]-[3(3b-2)+5]= equation:


Simplifying
3[3(b + -5) + 17] + -1[3(3b + -2) + 5] = 0

Reorder the terms:
3[3(-5 + b) + 17] + -1[3(3b + -2) + 5] = 0
3[(-5 * 3 + b * 3) + 17] + -1[3(3b + -2) + 5] = 0
3[(-15 + 3b) + 17] + -1[3(3b + -2) + 5] = 0

Reorder the terms:
3[-15 + 17 + 3b] + -1[3(3b + -2) + 5] = 0

Combine like terms: -15 + 17 = 2
3[2 + 3b] + -1[3(3b + -2) + 5] = 0
[2 * 3 + 3b * 3] + -1[3(3b + -2) + 5] = 0
[6 + 9b] + -1[3(3b + -2) + 5] = 0

Reorder the terms:
6 + 9b + -1[3(-2 + 3b) + 5] = 0
6 + 9b + -1[(-2 * 3 + 3b * 3) + 5] = 0
6 + 9b + -1[(-6 + 9b) + 5] = 0

Reorder the terms:
6 + 9b + -1[-6 + 5 + 9b] = 0

Combine like terms: -6 + 5 = -1
6 + 9b + -1[-1 + 9b] = 0
6 + 9b + [-1 * -1 + 9b * -1] = 0
6 + 9b + [1 + -9b] = 0

Reorder the terms:
6 + 1 + 9b + -9b = 0

Combine like terms: 6 + 1 = 7
7 + 9b + -9b = 0

Combine like terms: 9b + -9b = 0
7 + 0 = 0
7 = 0

Solving
7 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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